Math, asked by suryapratap51, 9 months ago

x=3-√8then find (x^2+1÷x^2)​

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Answered by birupakshya17
2

x= 3-√8

Then,

(x²+1/x²)

(3-√8)²+1/(3-√8)²

(3)²-2(3)(√8)+(√8)²+1/(3-√8)²

9-6√8+8+ 1/ 9+8-6√8

17-6√8 + 1/ 17-6√8

(17-6√8)²+1/(17-6√8)

(17)²-2(17)(6√8)+(6√8)²+1/(17-6√8)

289-204√8+288+1/(17-6√8)

578-204√8/17-6√8

Hope this helps you

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