x^3 +9x^2 +27x+27 factorise
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Answered by
4
Step-by-step explanation:
Heya ‼
x^3+9x^2+27x+27x3+9x2+27x+27
Rearranging the given cubic polynomial :
=x^3+27+9x^2+27x=x3+27+9x2+27x
=x^3+3^3+3×3x(x+3)=x3+33+3×3x(x+3)
As\:we\:know,Asweknow,
(a+b)^3 = a^3+b^3+3ab(a+b)(a+b)3=a3+b3+3ab(a+b)
Now, back\:to\:your\:question's\:solutionNow,backtoyourquestion′ssolution :
=x^3+3^3+3×3x(x+3)=x3+33+3×3x(x+3)
(x+3)^3(x+3)3
hope it helps you
Answered by
2
x^3 +9x^2 +27x+27 factorise
so the answer in the attachment document..
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