(x-3) and (x-1/3) are the factors of ax²-10x+b. show that a=b
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Answered by
1
Answer:
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Step-by-step explanation:
Let take x = 3 ( as x-3 is a factor )
Then the eqn.,
=> 9a + 15 + b = 0 __(1)
& x = 1/3 ( as x-1/3 is also a factor )
Then the eqn.,
=> a/9 + 5/3 + b = 0
=> a + 15 + 9b = 0 __(2)
Solving 1 & 2,
=> a = -3/2, & b = - 3/2. => a = b.
=) Hence proved.
Answered by
0
Answer:
Step-by-step explanation:
Let take x = 3 ( as x-3 is a factor )
Then the eqn.,
=> 9a + 15 + b = 0 __(1)
& x = 1/3 ( as x-1/3 is also a factor )
Then the eqn.,
=> a/9 + 5/3 + b = 0
=> a + 15 + 9b = 0 __(2)
Solving 1 & 2,
=> a = -3/2, & b = - 3/2. => a = b.
=) Hence proved.
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