Question

x^3 cos x differential coefficient​

Answer 1

Step-by-step explanation:

We have,

$y = {x}^{3} \cos(x)$

Differentiating both sides,

$\frac{dy}{dx} = 3 {x}^{2} \cos(x) + {x}^{3} ( - \sin(x) )$

$\implies \frac{dy}{dx} = 3 {x}^{2} \cos(x) - {x}^{3} \sin(x)$