x+3 is a factor of x*3+6x*2+5x-12
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Answer:
f(x) = x^3 +6x^2+5x-12
if x+3 is a factor then,
(x+3=0,x= -3)
f(-3)= should be 0
by factor theorem.
f(-3) =
(-3)^3 +6(-3)^2+5(-3)-12
= -27+54-15-12
= -54+54
= 0
therefore x+3 is a factor of x^3 +6x^2+5x-12.
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