Question

X=3, is one root of given quadratic equation x2-2kx-620 the find the value of k

Answer 1

Put the vqlue of x,
In this equation, so
(3)2-2k(3)-620
9-6k-620
611=6k
So,
611by6

Answer 2

${x}^{2} - 2kx - 620 = 0 \\ 9 - 6k - 620 = 0 \\ - 6k = 620 - 9 \\ - 6k = 611 \\ k = \frac{611}{ - 6}$