Question

. (x – 3) is the factor of polynomial (x^3− 3x^2+ ax − 10) then find the value of ‘a’. ​

Answer 1

Answer:

The value of $a$ is $-3\frac{1}{3}$.

Step-by-step explanation:

Zero of $(x-3)$ :

$x-3=0$

$x=0+3$

$x=3$

By Factor Theorem :

${x}^3-3{x}^2+ax-10=0$

${(3)}^3-3{(3)}^2-a(3)-10=0$

$27-(3*9)-3a-10=0$

$27-27-10-3a=0$

$-10-3a=0$

$-3a=10$

$a=\frac{-10}{3}$

$a=-3\frac{1}{3}$