Question

X^+3(m+1)x+4m+5=0 for what value of m the roots of the following equation are equal

Answer 1

Step-by-step explanation:

for equal roots D=b2-4ac= 0

= [2{m+1}]square-4m[3m+1]= 0

m2+2m+1-3m2-m= 0

= -2m2 + m -1= 0

=2m2-m-1=0=[m-1]{m+1/2}= 0

m= 1, -1/2