X = 3 root 28 and y = 3 root 27 find x+y -1 divided by x square +xy + y square
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so answer is 3. pls pls mark brainliest:-)
Step-by-step explanation:
here we use (x³-y³) formula.
(x³-y³)=(x-y)(x²+y²+xy)
so 1/(x²+y²+xy)=(x-y)/(x³-y³)
so substituting, we get the above expression to be
x+y-(x-y)/(x³-y³)
in denominator I'm putting x equals cube root 28 and y equals cube root 27.
so it becomes,
x+y-(x-y)/(28-27)=x+y-x+y=2y
= 2(27^1/3)=2×3=6
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