Question

(x + 3)square + (x - 3)square​

Answer 1

Answer:

$= ( {x + 3})^{2} + ( {x - 3}) ^{2} \\ = ({x}^{2} + 9 + 6x) + ({x}^{2} + 9 - 6x) = \\{x}^{2} +6 x + 9 + {x}^{2} + 9 - 6x \\ = 2 {x }^{2} + 18$

Answer 2

Answer:

2x square+18

Step-by-step explanation:

(x+3)square +(x-3)square

(by using identity(a+b)square=a square +b square +2ab

(a-b) square= a square +b square- 2ab)

therefore

(x square +9+6x)+(x square+9-6x)

2x square +18