x = 3+ under root 8 find the value of x sqaure + 1 upon x sqaure
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Answer:
Explanation:
x=3+√8
x²+1/x²
=(3+√8)²+1/(3+√8)²
=(3)²+2(3)(√8)+(√8)²+1/(3)²+2(3)(√8)+(√8)²
=9+6√8+8+1/(9+6√8+8)
=17+6√8+1/(17+6√8)
=[(17+6√8)²+1]/(17+6√8)
=[289+36(8)+1]/(17+6√8)
=(290+288)/(17+6√8)
=578/[17+6(2.83)]
=578/(17+16.98)
=578/33.98
=17.01
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