English, asked by digeesh3776, 10 months ago

x = 3+ under root 8 find the value of x sqaure + 1 upon x sqaure

Answers

Answered by divyanknaik62
0

Answer:

Explanation:

x=3+√8

x²+1/x²

=(3+√8)²+1/(3+√8)²

=(3)²+2(3)(√8)+(√8)²+1/(3)²+2(3)(√8)+(√8)²

=9+6√8+8+1/(9+6√8+8)

=17+6√8+1/(17+6√8)

=[(17+6√8)²+1]/(17+6√8)

=[289+36(8)+1]/(17+6√8)

=(290+288)/(17+6√8)

=578/[17+6(2.83)]

=578/(17+16.98)

=578/33.98

=17.01

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