Question

x+3 whole square + x-3 whole square ​

Answer 1

Answer:

12x

Step-by-step explanation:

here ..

we can use the formula..

a²-b² = (a+b)(a-b)

so..

(x+3)²-(x-3)²

= (x+3+x-3)(x+3-x+3)

=(2x)(6)

= 12x

..

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Answer 2

Given:

$(x+3)^2 + (x-3)^2$

To prove:

Find the value.

Solution:

Formula:

$\bold {(a+b)^2 = a^2+b^2+2ab}\\\\\bold{(a-b)^2 = a^2+b^2-2ab}$

Solve the given value:

$\rightarrow(x+3)^2 + (x-3)^2 \\\\\rightarrow (x^2+3^2+2 \times x \times 3)+ (x^2+3^2-2 \times x \times 3)\\\\\rightarrow (x^2+9+6x)+ (x^2+9-6x)\\\\\rightarrow 2x^2+18\\\\\rightarrow 2(x^2+9)$

The final value is = $\bold {2(x^2+9)}$