Question

x-3/x+1=1/2
solve the equation.​

Answer 1

⚘Answer

$\frac{x - 3}{x + 1} = \frac{1}{2} \\ \\ \\ \implies \ \: \mathcal {By \: Cross \: Muliply,} \\ \\ \\ \implies \: 2(x - 3) = 1(x + 1) \\ \\ \\ \implies \:2x - 6 = x + 1 \\ \\ \\ \implies \: 2x - x = 1 + 6 \\ \\ \\ \implies \: x = 7$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathscr{-@Nidhi}$

Answer 2

Answer:

• Value of x in the given equation is 7.

Step-by-step explanation:

$\bf{Q)}\;\sf{\dfrac{x-3}{x+1}=\dfrac{1}{2}}$

To Find:

• Value of x.

Solution:

According to the question,

$\sf{\implies\dfrac{x-3}{x+1}=\dfrac{1}{2}}$

By cross-multiplication,

$\sf{\implies2(x-3)=1(x+1)}$

Opening the brackets,

$\sf{\implies2x-6=x+1}$

Transposing variables to LHS, constants to RHS and changing its sign,

$\sf{\implies2x-x=1+6}$

Solving further,

$\bf{\implies x=7}$

Hence,

• x = 7

Verification:

We will substitute the value of x to the equation and see if LHS = RHS or not. If LHS = RHS, then our value for x is correct.

LHS:

$\sf{\longmapsto\dfrac{7-3}{7+1}}$

$\sf{\longmapsto\dfrac{4}{8}}$

$\sf{\longmapsto\dfrac{4\div4}{8\div4}}$

$\sf{\longmapsto\dfrac{1}{2}}$

RHS:

$\sf{\longmapsto\dfrac{1}{2}}$

As,

• LHS = RHS.

Hence, Verified.