X^3=x^1/2 then x=? Find the value of x
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Hello !!
Is very simple solve your question. See the resolution below.
x^3 = x^(1/2)
x^3 = √(x^1)
x^3 = √(x)
(x^3)^2 = (√(x))^2
x^(3 × 2) = x^((1/2) × 2)
x^(6) = x^(2/2)
x^(6) = x
x^(6) - x = 0
A solution for (x) is (0) because in the quadratic formula the coeficient (C) is 0.
Now , you find the other root.
x - 1 = 0
x = 0 + 1
x'' = 1
Final result : the solution for (x) are 0 and 1.
I hope I have collaborated !
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