Question

x^3-x^2-14x+24
How it is a factor of x+4 in p(x) form

Answer 1

Answer:

p(x)=x3-x2-14x+24

p(-4)=-64-16+56+24

-70+70 =0

so x3-x2-14x+24 is a factor of x+4

Answer 2

$\huge\mathcal\red{ANSWER}$

$x {3} - x {}^{2} - 14x + 24$

$\sf{p( - 4)} =x( - 4) {3} - x( - 4) {}^{2} +14( - 4) + 24$

$p( - 4) = - 64 - 16 - 56 + 24 \\ - 70 + 70 \\ = 0$

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