Question

x/3-(x-2)/2 equal to 7 upon 3​

Answer 1

Solution:

x/3 - (x-2)/2 = 7/3

=> [2x-3(x-2)]/6 = 7/3

=> (2x-3x+6)/6 = 7/3

=> (-x+6)/6 = 7/3

Multiply both sides by 3 , we get

=> (-x+6)/2 = 7

Do the cross multiplication, we get

=> (-x+6) = 2×7

=> -x + 6 = 14

=> -x = 14 - 6

=> -x = 8

=> x = -8

Therefore,

x = -8

•••••

Answer 2

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