x+3 x+2
----- + ----- = 2
x-3 x-2
SOLVE AND VERIFY
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Hi ,
It is given that ,
( x+ 3 )/( x - 3 ) + ( x + 2 )/( x -2 ) = 2
=> [(x+3)(x-2)+(x+2)(x-3)]/[(x-3)(x-2)]=2
=> [x²+x-6+x²-x-6]/(x²-5x+6)= 2
=> ( 2x² -12 ) = 2( x² - 5x + 6 )
=> 2x² - 12 = 2x² - 10x + 12
=> 2x² - 2x² + 10x = 12 + 12
=> 10x = 24
x = 24/10
x = 12/5
I hope this helps you.
: )
It is given that ,
( x+ 3 )/( x - 3 ) + ( x + 2 )/( x -2 ) = 2
=> [(x+3)(x-2)+(x+2)(x-3)]/[(x-3)(x-2)]=2
=> [x²+x-6+x²-x-6]/(x²-5x+6)= 2
=> ( 2x² -12 ) = 2( x² - 5x + 6 )
=> 2x² - 12 = 2x² - 10x + 12
=> 2x² - 2x² + 10x = 12 + 12
=> 10x = 24
x = 24/10
x = 12/5
I hope this helps you.
: )
Answered by
0
Hope it helps you....... please mark as brainliest
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