Question

(x + 3) (x^2 - 3y) + 3xy for x = 2, y = -1​

Answer 1

Answer:

$(x + 3)( {x}^{2} - 3y) + 3xy \\ (2 + 3)( {2 }^{2} - 3 \times ( - 1)) + 3 \times 2 \times (- 1) \\ 5 \times (4 + 3) + ( - 6) \\ 5 \times 7 - 6 \\ 35 - 6 \\ 29 > answer$

Answer 2

Answer:

5

Step-by-step explanation:

(x + 3) (x^2 - 3y) + 3xy

Substituting the value of x and y :

x = 2, y = -1

(x + 3) (x^2 - 3y) + 3xy

= (2 + 3) (2^2 - 3(-1) + 3(2)(-1)

= (5)(4+3-6)

= 5*1

= 5