x^3+x^2-4x-4
factorise
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Answer:
x³ + x² - 4x + 4
= x²(x + 1) - 4(x + 1)
Taking x + 1 common, we get:
= (x + 1)(x² - 4)
= (x + 1)(x² - 2²)
As, a² - b² = (a + b) (a + b),
= (x + 1)(x + 2)(x - 2)
Therefore, x³ + x² - 4x - 4 = (x+1)(x+2)(x-2)
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