x^3-x^2+6x-a divided by x-a
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Answer:
The remainder when x3 - ax2 + 6x - a is divided by x - a is 5a.
Step-by-step explanation:
Step 1:
Put sor= underline o
x - a = 0
x = a
Step 2:
Let p(x) = x ^ 3 - a * x ^ 2 + 6x - a
Putting x = alpha
p(a) = (a) ^ 3 - a * (a) ^ 2 + 6(a) - a =a^ 3 -a^ 3 +6a-a
=5a.
Thus, remainder = p(a) = 5a
I hope it helps please mark me as brainliest
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