x-3/x=2 find roots. by factorization
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⬇⬇Hey mate here is your answer ⬇⬇
x-3/x=2
x^2-3=2x
x^2-2x-3=0
x^2-3x+x-3=0
x(x-3)+1(x-3)=0
(x+1)(x-3)=0
x+1=0 ; x-3=0
x=-1 ; x=3
Therefore the roots are -1 and 3
Wish you a happy new year
if it helps the plz mark it as brainliest
x-3/x=2
x^2-3=2x
x^2-2x-3=0
x^2-3x+x-3=0
x(x-3)+1(x-3)=0
(x+1)(x-3)=0
x+1=0 ; x-3=0
x=-1 ; x=3
Therefore the roots are -1 and 3
Wish you a happy new year
if it helps the plz mark it as brainliest
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