x^3-x^2+x+1=0 find the value of x
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Answer:
x = 1
Step-by-step explanation:
Equation should be x³ - x² + x - 1
p(x) = x³ - x² + x - 1 = 0
Let us take g(x) = x - 1
g(x) = 0
x - 1 = 0
x = 1
p(-1) = (1)³ - (1)² + (1) - 1
= 1 - 1 + 1 - 1
= 0 + 0
= 0
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