Question

(x+3)(X+2)-(x-1)(X-2)is equal to 7​

Answer 1

Answer:

Given, 3(x+2)−2(x−1)=7

⇒3x+6−2x+2=7

⇒x+8=7

Subtract 8 on both sides,

x+8−8=7−8

⇒x=−1

Step-by-step explanation:

x =-1

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Answer 2

Answer:

$(x+3)(x+2)-(x-1)(x-2) \\ = {x}^{2} + 2x + 3x + 6 - ( {x}^{2} - 2x - x + 2) \\ = {x}^{2} + 5x + 6 - {x}^{2} + 3x - 2 \\ = 8x + 4$

Given,

This is equal to 7

$8x + 4 = 7 \\ 8x = 3 \\ x = \frac{3}{8}$

∴ Finally,x is equal to 3/8.