Question

x^3 +x^2-x+3 is divided by x-1
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Answer 1

$for \: zeroes$

$x - 1 = 0$

$x = 1$

put x=1 in given equation

${x}^{3 } + {x}^{2} - x + 3$

$( {1})^{3} + {1}^{2} - 1 + 3$

$1 + 1 - 1 + 3$

$= > 4$

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Answer 2

x-1=0

x = 1x=1

put x=1 in given equation

{x}^{3 } + {x}^{2} - x + 3x

3

+x

2

−x+3

( {1})^{3} + {1}^{2} - 1 + 3(1)

3

+1

2

−1+3

1 + 1 - 1 + 31+1−1+3

= > 4=>4