Question

|x-3|+(x-3)²+√x-3+|x+3|=0

find number of real values of x for which:-​

Answer 1

Real no. for value of x is 3, -3.

Step-by-step explanation:

If  we put 3 and -3 in the above equation, we get the solution,

                           

                                       ⇒ |x-3|+(x-3)²+√x-3+|x+3|=0

                                       ⇒    $|3-3|+(3-3)^{2} +\sqrt{3-3}+|-3+3|=0$

                                       ⇒ 0 = 0

Putting 3 and -3 in the place of x the answer becomes zero which can be seen from above.

Real nos. are the nos. that include the negative, positive, rational, decimals as well as fractions.