Question

(x+3)(x-3)=27 do it's quadratic equation
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Answer 1

$\bf{\blue{\huge{Solution:-}}}$

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(x + 3 ) ( x - 3) = 27

As we know,

$\boxed{\pink{(a + b)(a - b)=a^{2}-b^{2}}}$

Hence, we get

x² - 3² = 27

x² - 9 = 27

x² = 27 + 9

x² = 36

x = √36

x = ±6

=> x = 6 , x = -6

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Answer 2

$\mathfrak{What's\ a\ quadratic\ equation}$

$\textbf{A quadratic polynomial is of the form x ^2- px +q=0 where a, b and c are real numbers and a \neq0. }$

Coming to our question

Given,

(x+3)(x-3)=27

We know the identity, $\bf(a+b)(a-b)=a^2-b^2$

So here, a=x and b=3.

Using the identity,

$(x+3)(x-3)=27\\ x^2-9=27\\ x^2=27+9\\ x^2=36\\ x=\sqrt{36}\\ x=-6\ or\ +6$