Math, asked by magicalgamer551, 4 months ago

x-3/x+3=x-2/x+2


plzzz help​

Answers

Answered by Haritendra
0

Answer:

x-3/x+3 = x-2/x+2

(x-3/x+3)-(x-2/x+2) = 0

(x-3) (x+2) - (x-2) (x+3) / (x+3) (x+2) = 0

x^2-3x+2x-6-x^2-3x+2x+6 = 0

-6x+4x = 0

-2x = 0

x = 0/-2

x = 0. Ans.

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