x+3/x-3 - x-3/x+3=1 - x^2/x^2-9
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Answered by
1
Answer:
Rewrite
9
as
3
2
.
1
x
−
3
+
x
+
3
x
2
−
3
2
=
2
x
−
3
Since both terms are perfect squares, factor using the difference of squares formula,
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
where
a
=
x
and
b
=
3
.
1
x
−
3
+
x
+
3
(
x
+
3
)
(
x
−
3
)
=
2
x
−
3
Reduce the expression
x
+
3
(
x
+
3
)
(
x
−
3
)
by cancelling the common factors.
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1
x
−
3
+
1
x
−
3
=
2
x
−
3
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