Question

[√x+3-√x-3]\[√x+3-√x-3] differentiate​

Answer 1

Answer:

0

Explanation:

for (√x+3-√x-3)/(√x+3-√x-3)

numerator and denominator are equal so both of

them will get cancelled.

so,

(√x+3-√x-3)/(√x+3-√x-3)=1

now, differentiating the term we get

d/dx(√x+3-√x-3)/√x+3-√x-3) = d/dx(1)

we know that d/dx(k)=0

if k =1 then

d/dx (1) =0