(x+3)(x-4)=0find value
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Answered by
0
x²-4x+3x-12=0
x²-x-12=0
by using the equation -b±√b²-4ac/2a
x=-(-1)±√1²-4×1×-12/2×1
=1±√49/2
=1±7/2
=1+7/2 or 1-7/2
Answered by
2
Answer:
on multiplying x²-x-12
x²-4x+3x-12
x(x-4)+3(x-4)
(x+3)(x-4)
x=-3 & 4
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