Math, asked by pari97735, 1 year ago

(x+3)(x-4)=0find value​

Answers

Answered by Billina
0

x²-4x+3x-12=0

x²-x-12=0

by using the equation -b±√b²-4ac/2a

x=-(-1)±√1²-4×1×-12/2×1

=1±√49/2

=1±7/2

=1+7/2 or 1-7/2

Answered by vipin55
2

Answer:

on multiplying x²-x-12

x²-4x+3x-12

x(x-4)+3(x-4)

(x+3)(x-4)

x=-3 & 4

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