Math, asked by chinaydurhan, 10 months ago

(x-3)(x-4)^2 (x-5) -6 factorize

Answers

Answered by shayrakhan

0

Step-by-step explanation:

(x-3)(x^2+16-8x)-6x+30=0. x^3+16x-8x^2-3x^2-48+24x-6x+30=0 x^3-11x^2+34x -18=0. x^2(x-11) + 2 (17x-9) =0

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