Question

(x-3)(x-4)=34/33^2 find the value of x​

Answer 1

Step-by-step explanation:

$(x - 3)(x - 4) = \frac{34}{ {33}^{2} } \\ (x - 3)(x - 4) = \frac{34}{1089} \\ {x}^{2} - 4x - 3x + 12 = \frac{34}{1089} \\ {x}^{2} - 7x + 12 = \frac{34}{1089} \\ 1089( {x}^{2} - 7x + 12) = 34 \\ 1089 {x}^{2} - 7623x + 13068 = 34 \\ 1089 {x}^{2} - 7623x + 13068 - 34 = 0 \\ 1089 {x}^{2} - 7623x + 13034 = 0 \\ 1089 {x}^{2} - 3234x - 4389x + 13034 = 0 \\ 33x(33x - 98) - 133(33x - 98) = 0 \\ (33x - 98)(33x - 133) = 0 \\ 33x - 98 = 0 \: \: \: or \: \: \: 33x - 133 = 0 \\ 33x = 98 \: \: \: or \: \: \: 33x = 133 \\ \boxed{ \large{ x = \underline{ \underline{ \frac{98}{33}}} \: \: \: or \: \: \: x = \underline{ \underline{ \frac{133}{33} }}}}$