x+3/x=4 find x³+27/x³
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Answer:
27/64x³ +144x + 144x² +27
Step-by-step explanation:
x+3/x=4 find x³+27/x³
x+3=4x
x=4x-3 (put the value of x in question)
x³+27/x³
(4x-3)³+27/(4x-3)³
a³-3a²b+3ab²-b³ (formula of (a-b)³)
put this formula in equation)
(
(4x-3)³+27/(4x-3)³ ((4x-3)³ is under both (4x-3)³ and 27 *separately*)
(4x³-3(4x)²(-3) + 3(4x)(-3)²-(-3)³ + 27/(4x³-3(4x)²(-3) + 3(4x)(-3)²-(-3)³
(64x³-48x(-3) +144x² -(-3)³ + 27/ (64x³- 48x(-3) +144x² -(-3)³
64x³ +144x + 144x² +27 +27 / 64x³ +144x + 144x² +27
64x³ +144x + 144x² +27 /64x³ +144x + 144x² +27 + 27/64x³ +144x + 144x² +27 (cut off underlined ones)
27/64x³ +144x + 144x² +27
HOPE IT HELPS UHH... :)
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