Math, asked by kushaldhoot707, 7 months ago

x+3/x=4 find x³+27/x³​

Answers

Answered by aqsatufailrajput
1

Answer:

27/64x³ +144x + 144x² +27

Step-by-step explanation:

x+3/x=4 find x³+27/x³​

x+3=4x

x=4x-3    (put the value of x in question)

x³+27/x³​

(4x-3)³+27/(4x-3)³

a³-3a²b+3ab²-b³    (formula of (a-b)³)

put this formula in equation)

(

(4x-3)³+27/(4x-3)³       ((4x-3)³ is under both (4x-3)³ and 27 *separately*)

(4x³-3(4x)²(-3) + 3(4x)(-3)²-(-3)³ + 27/(4x³-3(4x)²(-3) + 3(4x)(-3)²-(-3)³

(64x³-48x(-3) +144x² -(-3)³ + 27/ (64x³- 48x(-3) +144x² -(-3)³

64x³ +144x + 144x² +27 +27 / 64x³ +144x + 144x² +27

64x³ +144x + 144x² +27 /64x³ +144x + 144x² +27   + 27/64x³ +144x + 144x² +27             (cut off underlined ones)

27/64x³ +144x + 144x² +27

HOPE IT HELPS UHH... :)

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