Question

(X+3) (x-4) का एक धनात्मक मान ?​

Answer 1

Step-by-step explanation:

$(x + 3)(x - 4) \\ {x}^{2} - 4x + 3x - 12 \\ {x}^{2} - x - 12$

I hope it helps you

Answer 2

Answer:

$\huge \tt{(x + 3)(x - 4)} \\ \huge\tt{ = {x}^{2} - 4x + 3x - 12} \\ \huge\tt{ = {x}^{2} - x - 12}$