x^3-x-4 using regula falsi method
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Answer:
Correct option is
A
1.78049
Here, f(x)=x
3
−x−4=0
first iteration:
]Here f(1)=−4<0 and f(2)=2>0
Now, root lies between x
0
=1 and x
1
=2
x
2
=x
0
−f(x
0
)×
f(x
1
)−f(x
0
)
x
1
−x
0
=1−(−4)×
2−(−4)
2−1
=1.66667
f(x
2
)=f(1.66667)=−1.03704<0
2nd iteration:
Here f(1.66667)=−1.03704<0 and f(2)=2>0
Now, root lies between x
0
=1.66667 and x
1
=2
x
3
=x
0
−f(x
0
)×
f(x
1
)−f(x
0
)
x
1
−x
0
=1.67−(−1.04)×
2−(−1.04)
2−1.67
=1.78049
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