(x-3)(x-4)+(X+3)(X+4)-x(2x-3)=0. solve the following equation by inverting and into linear equation
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(x-3)(x-4)+(X+3)(X+4)-x(2x-3)=0
(x² -4x -3x+12)+(x²+4x+3x+12) -( 2x²-3x)=0
(x² -4x -3x+12)+(x²+4x+3x+12) -( 2x²-3x)=0
(x² -7x +12)+(x²+7x+12) -( 2x²-3x)=0
2x² +24 -2x² +3x = 0
3x = 24
x= 8
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