(x+3 ) (x-5)= x^2-2x+_______
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Given that,
(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0
⇒x
2
+2x+3x+6+x
2
−3x−2x+6−2x
2
−2x=0
⇒2x
2
−2x
2
+5x−5x−2x+12=0
⇒−2x+12=0
⇒−2x=−12
⇒x=6
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