Question

x^3-x factorise the following​

Answer 1

Answer:

${x}^{3} - x = 0 \\ \\ = > x( {x}^{2} - 1) = 0 \\ \\ = > {x}^{2} - 1 = 0 \: \: or \: \: x \: = 0 \\ \\ = > {x}^{2} - 1 = 0 \\ = > (x + 1) \times (x - 1) = 0 \\ \\ = > x = - 1 \: \: or \: \: x = 1$

$x = 0 \\ \\ or \\ \\ x = 1 \\ \\ or \\ \\ x = - 1$

Answer 2

x

3

−x=0

=>x(x

2

−1)=0

=>x

2

−1=0orx=0

=>x

2

−1=0

=>(x+1)×(x−1)=0

=>x=−1orx=1

\begin{lgathered}\\ \\\end{lgathered}

$\begin{lgathered}x = 0 \\ \\ or \\ \\ x = 1 \\ \\ or \\ \\ x = - 1\end{lgathered}$