(x+3)(x²-3x+9) find the product of this equation
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We have
y=(x+3)(x2−3x+9) .
We need to expand this using the Distributive Property.
y=(x+3)(x2−3x+9)
=x⋅(x2−3x+9)+3⋅(x2−3x+9) .
We multiply these through to get
y=x3−3x2+9⋅x+3⋅x2−9x+27 .
Collecting like terms we have
y=x3+27 .
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