Question

(x-3)*(x²+4)*(x-2)^2020<0
Anyone please help me solve it ​

Answer 1

Answer;14

Step-by-step explanation:

first we will multiply (x-3)and(x^2-2)

=x(x^2+4)-3(x^2+4)

=x^3+4x-3x^2-12

=4x^4-3x^2-12

=x^2-12

the answer above should be again multiplied by (x-2)

=x(x^2-12)-2(x^2-12)

=x^3-12x-2x^2-24

=12x^2-2x^2-24

=10-24

=14