(x^3 y^2+5x^3 y^3+x^2 y^3)/(x^2 y^2 ) *
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Answer:
x−2y+3z=11−−−−−(1)
3x+y−z=2−−−−−−(2)
5x+3y+2z=3−−−−−(3)
Multiplying (1) with 3 and then solving with (2),we get,
10z−7y=31−−−−−(4)
Multiplying (1) with 5 and then solving with (3),we get,
z−y=4−−−−−−(5)
Now,multiplying (5) with 7 and then solving with (4),we get,
=>z=1
Putting the value of z in (5),
y=−3
putting the value of z and y in (1),
x=2
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