Math, asked by gregfermontilla, 7 months ago

(x^3 y^2+5x^3 y^3+x^2 y^3)/(x^2 y^2 ) *

Answers

Answered by rajvermaup1990
1

Answer:

x−2y+3z=11−−−−−(1)

3x+y−z=2−−−−−−(2)

5x+3y+2z=3−−−−−(3)

Multiplying (1) with 3 and then solving with (2),we get,

10z−7y=31−−−−−(4)

Multiplying (1) with 5 and then solving with (3),we get,

z−y=4−−−−−−(5)

Now,multiplying (5) with 7 and then solving with (4),we get,

=>z=1

Putting the value of z in (5),

y=−3

putting the value of z and y in (1),

x=2

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