Question

X^3+y^3-12xy+64 when x+y = - 4
please give the full solution.....

Answer 1

Answer:

Step-by-step explanation:

x³ + y³ + 12xy - 64

x³ + y³ - 4³ + 3(4xy) (64 = 4³)

(x + y - 4)(x² + y² + 4² - xy - 4y - 4x)

x + y = + 4

( 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)

0 * (x² + y² + 4² - xy - 4y - 4x)

= 0