x^3+y^3-12xy+6y when x+y is 64
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x³ + y³ - 12xy + 64
x³ + y³ + 4³ - 3(4xy) (64 = 4³)
(x + y + 4)(x² + y² + 4² - xy - 4y - 4x)
x + y = - 4
(- 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)
0 * (x² + y² + 4² - xy - 4y - 4x)
Answer = 0
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