Question

x/3+y/3=14;5x/6-y/3+7=0 by elimination method ​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given,

x/3+y/3=14

(Multiplying both sides by 3),

x+y=42........ (1)

5x/6-y/3=0

(Multiplying Both sides by 6)

5x-2y=0........(2)

Now,

(1)+(3),

x+5x+y-y=42+0

6x=42

x=42/6

x=7

Now putting the value of x=7 in equation (1) we get,

7+y=42

y=42-7

y=35