Question

x^3+y^3-3xy(x+y)=???????​

Answer 1

Answer:

Step-by-step explanation:

$x^{3} + y^{3} - 3xy ( x + y)$ =  $(x-y)^{3}$

Explanation:

$(x-y)^{3} =(x-y)(x-y)(x-y)$

Expand the first two brackets:

(x−y)(x−y)=$x^{2} -xy-xy+y^{2}$

⇒$x^{2} +y^{2} -2xy$

Multiply the result by the last two brackets:

$(x^{2} +y^{2} -2xy)(x-y)$ =$x^{3} -x^{2} y+xy^{2} - y^{3} - 2x^{2} y+2xy^{2}$

⇒$x^{3} -y^{3} -3x^{2} y+3xy^{2}$

Always expand each term in the bracket by all the other terms in the other brackets, but never multiply two or more terms in the same bracket.

Thank U : )

Answer 2

Answer:

I think its $(x - y)^{3}$

Step-by-step explanation:

Thank YoU