x^3 + y^3 if x + y = 3 and xy =2
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Answered by
3
x+y=3
cubing on both sides
(x+y)^3=27
x^3+y^3+3xy(x+y)=27
x^3+y^3=27-3(2)(3)
=27-18
=9
cubing on both sides
(x+y)^3=27
x^3+y^3+3xy(x+y)=27
x^3+y^3=27-3(2)(3)
=27-18
=9
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Answered by
1
x + y =3
x³+y³=(x+y)³-3(xy)(x+y)
=3³-3(3)(2)
=27-18
=9.
x^3 + y^3=9
x³+y³=(x+y)³-3(xy)(x+y)
=3³-3(3)(2)
=27-18
=9.
x^3 + y^3=9
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