Math, asked by ritikajaiswal37, 9 months ago

x^3+y^3 if x+y=3 and xy=2

Answers

Answered by renuagrawal393

5

Answer:

x³+y³=(x+y)³-3xy(x+y)

=(3)³-3(2)(3)

=27-18=9

hope it helps you.....

Answered by MяMαgıcıαη

24

Answer:

x³ + y³ = ( x + y) ³ - 3xy( x + y)

= 3³ - 3*2*3

= 27 - 18

= 9

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