Question

x^3+y^3, if x+y=3, and xy=2​

Answer 1

Answer:

9

Step-by-step explanation:

first (x+y)^2= x^2 + y^2 + 2xy

3^2= x^2 +y^2 + 2(2)

9 = x^2 + y^2 + 4

9-4= x^2 + y^2

5 = x^2 +y^2

now

x^3+y^3 = (x+y)(x^2 + y^2 - xy)

x^3+y^3 = (3)((5) - (2))

x^3+y^3= 3*3

x^3+y^3 = 9