x^3+y^3 when x+y=12,xy=27
Answers
Answered by
0
Answer:
756
Step-by-step explanation:
(x-y)^2=(x+y)^2-4xy
=144-108
(x-y)^2=36
x-y=6---(1)
x+y=12---(2)
by solving eq (1),(2)
we get
x=9,y=3
x^3 +y^3=9^3+3^3
=756
Answered by
0
Answer:
756
Step-by-step explanation:
x+y=12
xy=27
x^3+y^3 =( x+y) (x^2-xy+y^2)
=12 (x^2+y^2-27)
Since we don't know about the value of x^2+y^2,
(x+y)^2= x^2+y^2+2xy
144=x^2+y^2+54
x^2+y^2=90
So,
x^3+y^3= 12(90-27)
= 12(63)
=756
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