(x) 3+(y) 3(x+y) {(x) 2-xy+(y) 2} if x=1, y=2
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Answer:
(x)3+(y)3(x+y){(x)2-xy+(y)2}
substitute x = 1 ,y = 2
(1)3+(2)3(1+2){(1)2-(1)(2)+(2)2}
= 3+6(3){2-2+4}
= 3+6(3){4}
= 3+6(12)
= 3+72= 75
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